WebGLRenderingContext: viewport() method
{{APIRef("WebGL")}}
{{AvailableInWorkers}}
The WebGLRenderingContext.viewport()
method of the WebGL API sets the viewport, which specifies
the affine transformation of x and y from normalized device coordinates to window
coordinates.
Syntax
viewport(x, y, width, height)
Parameters
x
- : A
{{domxref("WebGL_API/Types", "GLint")}}
specifying the horizontal coordinate for the lower left corner of the viewport origin. Default value: 0.
- : A
y
- : A
{{domxref("WebGL_API/Types", "GLint")}}
specifying the vertical coordinate for the lower left corner of the viewport origin. Default value: 0.
- : A
width
- : A non-negative
{{domxref("WebGL_API/Types", "GLsizei")}}
specifying the width of the viewport. Default value: width of the canvas.
- : A non-negative
height
- : A non-negative
{{domxref("WebGL_API/Types", "GLsizei")}}
specifying the height of the viewport. Default value: height of the canvas.
- : A non-negative
Return value
None ({{jsxref("undefined")}}
).
Exceptions
If either width or height is a negative value, a
gl.INVALID_VALUE
error is thrown.
Examples
When you first create a WebGL context, the size of the viewport will match the size of
the canvas. However, if you resize the canvas, you will need to tell the WebGL context a
new viewport setting. In this situation, you can use gl.viewport
.
gl.viewport(0, 0, canvas.width, canvas.height);
The viewport width and height are clamped to a range that is implementation dependent.
To get this range, you can use the MAX_VIEWPORT_DIMS
constant, which
returns an {{jsxref("Int32Array")}}
.
gl.getParameter(gl.MAX_VIEWPORT_DIMS);
// e.g. Int32Array[16384, 16384]
To get the current viewport, query the VIEWPORT
constant.
gl.getParameter(gl.VIEWPORT);
// e.g. Int32Array[0, 0, 640, 480]
Specifications
{{Specifications}}
Browser compatibility
{{Compat}}
See also
{{domxref("WebGLRenderingContext.scissor()")}}
{{domxref("WebGLRenderingContext.getParameter()")}}